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Polynomial function in standard form with zeros 5,-4,1

1 Answer

5 votes

Answer:


\boxed{\sf \ \ \ x^3-2x^2-19x+20 \ \ \ }

Explanation:

hello,

by definition we can write


(x-5)(x+4)(x-1)

as 5,-4,1 are the zeroes

now we have to write it in the standard form, let's do it


(x-5)(x+4)(x-1)=(x^2+4x-5x-20)(x-1)\\=(x^2-x-20)(x-1)=x^3-x^2-20x-x^2+x+20\\=x^3-2x^2-19x+20

hope this helps

User Chnossos
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