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Find the value of x in the given right triangle

Find the value of x in the given right triangle-example-1
User Kanuos
by
5.1k points

2 Answers

3 votes

Answer:

5.6

Explanation:

NOT 6.


cos62=(x)/(12)


12cos(62)=x


12cos(62)

^^ for the last part i couldn't add the multiplication symbol so ill just type it out

12 · cos(62)

and so, that would equal 5.63365.... but since we have to round it to the nearest 10ths it will be 5.6 :)

btw symbolab.com is a great ( calculator ) website for stuff like this

User Sajadre
by
4.9k points
4 votes

Answer:

The answer is 6

Explanation:

To find x we use cosine

cos∅ = adjacent / hypotenuse

From the picture

x is the adjacent

12 is the hypotenuse

∅ = 62°

So we have


\cos(62) = (x)/(12) \\ x = 12 \cos(62) \\ x = 5.633

The final answer is

6.00 to the nearest tenth.

Hope this helps you

User Jordan Maduro
by
5.2k points