1). Draw a perpendicular from point A to side BC. Let AD = h
2). sin A = h/c and sin C = h/a
3). h = c Sin A, h = a sin C
4). c Sin A =a sin C
5). Divide both side by Sin A * Sin C
6). c Sin A/(Sin A * Sin C) =a sin C/(Sin A * Sin C)
7). c/sin C = a/Sin A
8). Similarly prove that, c/sin C = b/Sin B
9). c/sin C = b/Sin B = a/Sin A
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