Question

a beam of 1mev electrons strike a thick target. for a beam current of 100 microampere, find the power dissipated in the target

Answer 1

power dissipated in the target is 100 W

Step-by-step explanation:

given data

electrons = 1 mev =
`10^(6)` eV

1 eV = 1.6 ×
`10^(-19)` J

current = 100 microampere = 100 ×
`10^(-6)` A

solution

when energy of beam strike with 1 MeV so energy of electron is

E = e × v ...................1

e is charge of electron and v is voltage

so put here value and we get voltage

v = 1 ÷ 1.6 ×
`10^(-19)`

v =
`10^(6)` volt

so power dissipated in target

P = voltage × current ..............2

put here value

P =
`10^(6)` × 100 ×
`10^(-6)`

P = 100 W

so power dissipated in the target is 100 W