Question

Two charged concentric spheres have radii of 0.008 m and 0.018 m. The charge on the inner sphere is 3.62 10-8 C and that on the outer sphere is 1.62 10-8 C. Find the magnitude of the electric field (in N/C) at 0.012 m.

Answer 1

The electric field is
`E = 2.2625 *10^(6) \ N/C`

Step-by-step explanation:

From the question we are told that

The radius of the inner sphere is
`r_1 = 0.008\ m`

The radius of the outer sphere is
`r _2 = 0.018 \ m`

The charge on the inner sphere is
`q_1 = 3.62 *10^(-8) \ C`

The charge on the outer sphere is
`q_2 = 1.62 *10^(-8) \ C`

The position from the origin is
`d = 0.012 \ m`

Generally the electric field is mathematically represented as

`E = (k (q_1 ))/( r^2)`

The reason for using
`q_1` for the calculation is due to the fact that the position considered is greater than the
`r_1` but less than
`r_2`

Here k is the Coulomb constant with value
`k = 9*10^(9) \ kg\cdot m^3\cdot s^(-4) \cdot A{-2}`

So

`E = (9*10^9 (3.62 *10^(-8))/(0.012^2)`

`E = 2.2625 *10^(6) \ N/C`