Question

If Kb = 1.6 x 10−6, calculate the pH of solution of 0.0015 M morphine. Justify any approximations you make

Answer 1

4.3

Step-by-step explanation:

Data provided in the question as per the question is as follows

`k_b = 1.6 * 10^(-6)`

Now we use the log in both the sides

So,

`Pk_b = -log\ k_b = -log (1.6 * 10^(-6))`

`Pk_b` = 5.795

And, C = 0.0015

log c = -2.823

Now pH is

`= (1)/(2) (Pk_b - log\ c)`

`= (1)/(2) (5.795 - (-2.823))`

= 4.3

Hence, the pH of the solution of 0.0015 M morphine is 4.3 and the same is to be considered by applying the above formulas and the calculations part