Question

A balloon has a volume of 0.56 L and a pressure of 1.34 atm. The balloons pressure decreased to 0.85 atm,

what is the balloons new volume? Write your solution, including the formula used.

Answer 1

`\large \boxed{\text{0.88 L}}`

Step-by-step explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

`p_(1)V_(1) = p_(2)V_(2)`

Data:

`\begin{array}{rcrrcl}p_(1)& =& \text{1.34 atm}\qquad & V_(1) &= & \text{ 0.56 L} \\p_(2)& =& \text{0.85 atm}\qquad & V_(2) &= & ?\\\end{array}`

Calculations:

`\begin{array}{rcl}\text{1.34 atm} * \text{0.56 L} & =& \text{0.85 atm} * V_(2)\\\text{0.750 L} & = & 0.85V_(2)\\V_(2) & = &(0.750)/(0.85)\\\\& = &\textbf{0.88 L}\\\end{array}\\\text{The balloon's new volume is $ \large \boxed{\textbf{0.88 L}}$}`