Question

An overhead projector lens is 32.0 cm from a slide (the object) and has a focal length of 30.1 cm. What is the magnification of the image? (Unit=cm) PLS HELP

Answer 1

M = -15.8

Step-by-step explanation:

object distance = 32cm

focal length = 30.1 cm

To find M we first need to find di or image distance

I will use the equation: 1/f = 1/di + 1/do

By changing the equation to 1/f - 1/di = 1/do we get 0.0019725

equation with numbers plugged in:

1/30.1 - (1/32) = 0.0019725

To change 1/do to do we divide 1 by 0.0019725

You should get 506.97

Now use the equation

M = -(di/do)

M = -(506.97/32)

You should get M = -15.8

Answer 2

Answer: M = 14.3

Step-by-step explanation:

Given the following :

Object distance (u) = 32cm

Focal length (f) = 30.1 cm

Magnification = image distance (v) / object distance (u)

Recall ; 1/f = 1/u + 1/v

1/30.1 = 1/32 + 1/v

1/v = 1/30.1 - 1/32

1/v = (32 - 30.1) / 963.2

1/v = 2.1 / 963.2

1/v = 0.0021802

v = 1/0.0021802

v = 458.66666 cm

Therefore, Magnification 'M' = v / u

M = 458.66666 / 32

M = 14.333333

M = 14.3