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Find the approximations T10, M10, and S10 for π 7 sin x dx. 0 (Round your answers to six decimal places.)

User Dankilman
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1 Answer

4 votes

Answer:

Explanation:

Well, since it was not given the interval let's use the interval [0,5] with n=10

So now, for the Trapezoidal Rule to approximate the area enclosed by the Integral of:
f(x)=7\pi \sin(x)


T_(10)=(b-a)/(2n)[f(a)+2f(x_1)+ ....2f(x_(n-1))+f(b)] Plugging in:


T_(10)=(5-0)/(2*10)[f(0)+2f((1)/(2))+2f(1)+2f((3)/(2))+2f(2)+2f(5/2)+2f(3)+2f(7/2)+2f(4)+2f(9/2) +f(5)]


T_(10)=(1)/(4)[0+21.086+37+43.87+39.99+26.322+6.20-15.43-33.285-42.99-21.087]


T_(10)\approx 15.419

Now the same area according to Simpson rule:


S_(10)=(b-a)/(3n)[f(a)+4f(x_(1))+2f(x_(2))+4f(x_(3) )+2f(x_(4))+4f(x_(5))+2f(x_(6))+4f(x_(7))+2f(x_(8))+4f(x_(9))+f(b)]\\S_(10)=(5)/(3*10)[0+74.01+43.87+79.98+26.322+12.413-15.43-66.571-42.99-21.08]\approx 15.085


S_(10)\approx 15.0585

User Amance
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