Question

I NEED HELP ASAP PLEASE, THANKS! :)

Answer 1

`(6^2-3^2)/(2)=(27)/(2)`

Explanation:

You can go to the trouble to integrate y = x from 3 to 6, or you can figure the area geometrically.

`\displaystyle\int_3^6{x}\,dx=\left.(x^2)/(2)\right|_3^6=(6^2-3^2)/(2)\quad\text{using integration}\\\\A=(1)/(2)(b_1+b_2)h=(1)/(2)(6+3)(6-3)=(6^2-3^2)/(2)\quad\text{using geometry}`