Question

a sandbag is released from a rising air balloon and hits the ground 7 seconds later. from what height was the sandbag dropped from if at teh moment of release the balloon was traveling upward at 3m/s

Answer 1

0.46

Step-by-step explanation:

We can solve this problem using the suvat equations of motions.

the height, s is what we are trying to find out

initial velocity, u = 3 m/s from the question

final velocity, v = 0 m/s since it hits the ground it will stop moving downwards

acceleration, a = -9.81, due to gravity

time, t =7, from the question.

v² = u² + 2as ⇒ v²-u² = 2as

⇒ s =
`(v^(2) -u^(2) )/(2a)`

⇒ s =
`(0^(2) -3^(2) )/(-19.62)`

⇒ s = 9/19.62

⇒ s ≈ 0.46