Answer:
The height of the building is approximately 18 meters.
Explanation:
The question is:
FROM THE HIGH PART OF A WALL OF 8M HEIGHT, YOU CAN SEE THE LOW AND HIGH PART OF A BUILDING WITH ELEVATION AND DEPRESSION ANGLES OF 37° AND 45° RESPECTIVELY. CALCULATE THE HEIGHT OF THE BUILDING A.18 B.14 C.12 D.24 E.16
Solution:
Consider the diagram below.
Consider the triangle ABC.
Compute the value of y as follows:
![tan\ 37^(o)=(AB)/(BC)](https://img.qammunity.org/2021/formulas/mathematics/high-school/r2wp6fjqnnaf9kc5x8rk7i1qocq5b3t5vi.png)
![0.754=(8)/(y)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ri7ji75bvf7y5mfbx8wv6zy589u4ckyl4y.png)
![y=(8)/(0.754)](https://img.qammunity.org/2021/formulas/mathematics/high-school/z82gmqe1m15v8jhsyeipzam54o8rea6nxy.png)
![=10.61\\\approx 11](https://img.qammunity.org/2021/formulas/mathematics/high-school/ro0o4y35rx2qcovv8d2bh8i91qwyzc0as1.png)
Thus, the length of side AD is also 11 meters.
Now consider the triangle AED.
Compute the value of x as follows:
![tan\ 45^(o)=(AE)/(ED)](https://img.qammunity.org/2021/formulas/mathematics/high-school/1ravjaedz63l94p08gem7ta2f773dsigld.png)
![1=(11)/(x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/fxk496fcvcpzvobr88m1gl8z22m8s3gr63.png)
![x=11](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qnx576ueidzhej5xuoco015weayss0eaec.png)
Then the height of the building is:
![\text{Height of the Building}=x+8](https://img.qammunity.org/2021/formulas/mathematics/high-school/t2e1kscqu4nebplnonouxd2u6ns2hx5mjd.png)
![=11+8\\=19](https://img.qammunity.org/2021/formulas/mathematics/high-school/x037tsbfc2wts7ye6io81twf2kz1589lyt.png)
From the options provided it can be concluded that the height of the building is approximately 18 meters.