Question

Suppose that the distribution of lifetimes of females in France is not symmetric. According to Chebyshev's Theorem, at least approximately what percentage of these lifetimes are within k=3.8 standard deviations of the mean?

Answer 1

93.7% of the lifetimes are within 3.8 standard deviations of the mean

Explanation:

Generally Chebyshev's Theorem, can be mathematically represented as

`1 - (1)/(k^2)`%

The percentage of these lifetimes that are within k=3.8 standard deviations of the mean is mathematically evaluated using Chebyshev's Theorem as follows

`1 - (1)/(k^2)`%
`= (1 - (1)/(3.8^2) )`% =
`= 93.07`%

So from the above calculation we see that 93.7% of the lifetimes are within 3.8 standard deviations of the mean