Question

A certain superconducting magnet in the form of a solenoid of length 0.550 m can generate a magnetic field of 9.20 T in its core when its coils carry a current of 140 A. Find the number of turns in the solenoid.

Answer 1

28,750 turns

Explanation:

According to the given situation the solution of number of turns in the solenoid is shown below:-

Number of turns in the solenoid is

`B = (\mu_0NI)/(I)`

`N = (BI)/(\mu_oI)`

`N = \frac{(9.20)(0.550)}{4\pi*10{-7}(140)}`

`N = (5.06)/(0.000176)`

= 28,750 turns

Therefore for computing the number of turns in the solenoid we simply applied the above formula.

So, the right answer of number of turns in the solenoid is 28,750 turns.