Question

Find the equation of a line perpendicular to 4x+2y=3 that contains the point (1,5)

Answer 1

x -2y = -9

Explanation:

We can start by swapping the coefficients of x and y, then negating one of them. We can finish by evaluating the expression at the given point to find the constant.

2x -4y = constant

2(1) -4(5) = -18 = constant

So, an equation could be ...

2x -4y = -18

We notice that all of the coefficients of this equation are divisible by 2, so we can remove a factor of 2 from the equation:

x -2y = -9