Which function has real zeros at x = 3 and x = 7? f(x) = x2 + 4x - 21 Cf(x) = x2 - 4x - 21 Cf(x) = x2 - 10x + 21 f(x) = x2 - 10x - 21

asked May 13, 2021 66.1k views

5 votes

Which function has real zeros at x = 3 and x = 7?

f(x) = x2 + 4x - 21
Cf(x) = x2 - 4x - 21
Cf(x) = x2 - 10x + 21
f(x) = x2 - 10x - 21

4.2k points

Please log in or register to add a comment.

2 votes

Answer:

f(x) = x2 – 10x + 21

Explanation:

I got it because you substract and add the last part

4.3k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.6m questions

5.9m answers