Question

Write an equation for the nth term of the geometric sequence. Then find a sub 6

The values are -192, 48, -12, and 3​

Answer 1

`a_n = -192((-1)/(4))^(n-1)`

`a_6= (3)/(16)`

Explanation:

Explicit Formula:
`a_n = a_1(r)^(n-1)`

Step 1: Find r

-192/48 = -4

So we are dividing -4 or multiplying -1/4

Step 2: Write explicit formula

`a_n = -192((-1)/(4))^(n-1)`

Step 3: Find
`a_6`

`a_6 = -192((-1)/(4))^(6-1)`

`a_6= (3)/(16)`