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Find the vertex of the function given below y=x^2-2x+1

User Nohelia
by
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1 Answer

6 votes

Hey there! :)

Answer:

(1, 0).

Explanation:

Convert from standard form to vertex form by completing the square:

y = x² - 2x + 1

Move 1 to the other side:

-1 = x² - 2x

Complete the square. Remember to add to both sides:

-1 + (1) = x² -2x + 1

Simplify:

0 = (x - 1)²

The function in vertex form is:

y = (x - 1)²

Therefore, the vertex is:

(1, 0).