Question

What is the value of c in the equation below?

2(to the negative fourth power) • 2 (to the positive second power) = a(To the power of “b”) = c

A) -4
B) -2
C) 1/64
D) 1/4

Answer 1

D

Explanation:

Using the rules of exponents

`a^(m)` ×
`a^(n)` =
`a^((m+n))` and
`a^(-m)` =
`(1)/(a^(m) )`

Given

`2^(-4)` × 2² =
`2^((-4+2))` =
`2^(-2)` = c , hence

c =
`2^(-2)` =
`(1)/(2^(2) )` =
`(1)/(4)` → D

Answer 2

The answer is option D.

Explanation:

2^-4 • 2² = a^b = c

Use the rules of indices

Since the bases are the same and they are multiplying we add the exponents

That's

2^-4 + 2 = a^b = c

2^-2 = a^b = c

a^b = 2^-2

c = 1/4

Hope this helps you.