Answer:
so the factors of x²+3x-4 are (x-1)(x+4
Explanation:
Let x²+3x-4=0
by using sum and product rule
x²+4x-1x-4=0
Taking common
x(x+4)-1(x+4)=0
(x-1)(x+4)=0
i hope this will help you :)
(x - 1) (x + 4)
Product = -4
Sum = 3
Factors = -1 , 4
x² + 3x - 4 = x²- 1x + 4x - 4
= x(x -1) + 4(x - 1)
= (x - 1) (x + 4)
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