Question

Us

A 13.3 kg box sliding across the ground
decelerates at 2.42 m/s2. What is the
coefficient of kinetic friction?
(No unit)

Answer 1

0.242

Step-by-step explanation:

m = 13.3 kg

a =d= 2.42 m/s²

g = 10 m/s²

from the laws of friction F = ¶R

===> ¶ = F/R = ma/mg = a/g

¶ = a/g = 2.42/10 = 0.242