Question

1) A net force of 75.5 N is applied horizontally to slide a 225 kg crate across the floor.

a. Compute the acceleration of the crate?

Answer 1

The acceleration of the crate is
`0.3356\,(m)/(s^2)`

Step-by-step explanation:

Recall the formula that relates force,mass and acceleration from newton's second law;

`F=m\,a`

Then in our case, we know the force applied and we know the mass of the crate, so we can solve for the acceleration as shown below:

`F=m\,a\\75.5\,N=225\,\,kg\,\,a\\a=(75.5)/(225) \,(m)/(s^2) \\a=0.3356\,\,(m)/(s^2)`