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Write the standard equation of the circle with center (4, -2) and radius 5.2.

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Answer:

If the radius is really 5.2, then the standard equation of this circle is:


(x-4)^2+(y+2)^2=27.04

Now, if there was a typo in your question, and the radius is "5", then, the equation becomes:


(x-4)^2+(y+2)^2=25

Explanation:

Recall that the standard equation for a circle of radius R, centered at
(x_0,y_0), is given by:


(x-x_0)^2+(y-y_0)^2=R^2

Therefore in the case of a circle of radius R = 5.2, and centered at (4, -2), we have:


(x-x_0)^2+(y-y_0)^2=R^2\\(x-4)^2+(y-(-2))^2=(5.2)^2\\(x-4)^2+(y+2)^2=27.04

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