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5 votes
What are the zeroes of f(x) = y2 - 2x - 3?

2 Answers

4 votes

Answer:

x=y^2/2 - 3/2

Explanation:

User Tianissimo
by
5.4k points
3 votes

Answer:

Explanation:

Product = -3

Sum = -2

Factors = -3 , 1

y² - 2y - 3 = y² + y - 3y - 3

= y( y + 1) - 3(y + 1)

= (y +1) (y - 3)

User Davey
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5.2k points