Question

Please answer this....​

Answer 1

c)
`2(23)/(30)` d)
`1(23)/(24)`

7) a.
`6(3)/(11)` kg b.
`6 (2)/(3)` cm c. 20 cm

d.
`9(9)/(10)` kg e. 10 g f.
`23 (1)/(4)` kg

Explanation:

c)
`8(2)/(3)` -
`5(9)/(10)`

First we will change to improper fraction and then solve

`(26)/(3) - (59)/(10)`

=
`(260 - 177)/(30)`

=
`(83)/(30)`

we will now change to mixed number

=
`2(23)/(30)`

d)
`8(1)/(8) - 6(1)/(6)`

we will first change it to improper fraction and then solve

=
`(65)/(8) - (37)/(6)`

=
`(390 - 296)/(48)`

=
`(94)/(48)`

we can reduce the fraction

=
`(47)/(24)`

we will change it mixed number

=
`1(23)/(24)`

7)

a.
`(3)/(11)` of 23

=
`(3)/(11)` × 23

=
`(69)/(11)`

=
`6(3)/(11)` kg

b.
`(2)/(3)` of 10 cm

=
`(2)/(3)` × 10 cm

=
`(20)/(3)` cm

=
`6 (2)/(3)` cm

c.
`(5)/(6)` of 24cm

=
`(5)/(6)` × 24 cm

6 will divide 24

=5 × 4 cm

= 20 cm

d.
`(3)/(10)` of 33 kg

=
`(3)/(10)` × 33 kg

=
`(99)/(10)` kg

=
`9(9)/(10)` kg

e.
`(2)/(7)` of 35 g

=
`(2)/(7)` × 35 g

7 will go into 35

=2×5 g

=10 g

f.
`(3)/(4)` of 31 kg

=
`(3)/(4)` × 31 kg

=
`(93)/(4)` kg

=
`23 (1)/(4)` kg