185k views
1 vote
What value of x is in the solution set of 9(2x + 1) < 9x – 18?
Ο Ο Ο Ο
-2

2 Answers

1 vote
Answer:
x < -3

Step-by-step explanation:

step 1 - distribute

9(2x + 1) < 9x - 18
18x + 9 < 9x - 18

step 2 - subtract nine x from both sides of the expression

18x + 9 < 9x - 18
18x - 9x + 9 < 9x - 9x - 18
9x + 9 < -18

step 3 - subtract nine from both sides of the expression

9x + 9 < -18
9x + 9 - 9 < -18 - 9
9x < -27

step 4 - divide both sides of the expression by nine

9x < -27
9x/9 < -27/9
x < -3

Therefore, x < -3.
User Klaudio
by
8.0k points
4 votes

Answer:

x < -3

Step-by-step explanation:

9(2x + 1) < 9x – 18

18x +9 < 9x – 18

-9x -9x

9x +9 < – 18

-9 -9

9x < – 27

÷9 ÷9

x < -3

HOPE THIS HELPS:)

User Patrick Klitzke
by
9.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories