Answer:
The distance between the light and the actor's face is 29.24 ft
Explanation:
In the attached photo, you can see where the hypotenuse, the opposite side, and and adjacent side are located from the given angle measurement which is 70°. Our known side length is 10 ft which is our adjacent side and our variable is the hypotenuse. So, we will use cos.

Let's plug in our numbers and variable.

Since our hypotenuse is a variable, we are going to flip the equation so we can find the value of the hypotenuse which is also our variable.

Divide 10 by (cos)70.
x = 29.24
So, the hypotenuse is 29.24 feet which shows the distance between the light and the actor's face.