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PLZ HELP!! WILL MARK BRANLYIST!!! 30 POINTS!!

PLZ HELP!! WILL MARK BRANLYIST!!! 30 POINTS!!-example-1

1 Answer

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Answer:

The distance between the light and the actor's face is 29.24 ft

Explanation:

In the attached photo, you can see where the hypotenuse, the opposite side, and and adjacent side are located from the given angle measurement which is 70°. Our known side length is 10 ft which is our adjacent side and our variable is the hypotenuse. So, we will use cos.


Cos=(adjacent)/(hypotenuse)

Let's plug in our numbers and variable.


(Cos)70=(10)/(x)

Since our hypotenuse is a variable, we are going to flip the equation so we can find the value of the hypotenuse which is also our variable.


x=(10)/((cos)70)

Divide 10 by (cos)70.

x = 29.24

So, the hypotenuse is 29.24 feet which shows the distance between the light and the actor's face.

PLZ HELP!! WILL MARK BRANLYIST!!! 30 POINTS!!-example-1
User James Dobson
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