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If f(x) = 1/6 x-8, then f^-1(x)=
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If f(x) = 1/6 x-8, then f^-1(x)=

If f(x) = 1/6 x-8, then f^-1(x)=-example-1
User Oleg Vikoultsev
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2 Answers

2 votes

Answer:f(-1/6)-8

Explanation:

cuz

User HariShankar
by
9.1k points
3 votes

Answer:

f^-1(x) is 6x + 48

f(x) = 1/6x - 8

To find f^-1(x) equate f(x) to y

That's

f(x) = y

y = 1/6x - 8

Next interchange the terms

We have

x = 1/6y - 8

Make y the subject

Multiply through by 6

We have

6x = y - 48

y = 6x + 48

Therefore f^-1(x) is 6x + 48

Hope this helps you

User Brokentypewriter
by
8.5k points
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