Answer:
The correct answer is 1335.4 J/ °C.
Step-by-step explanation:
Based on the given information, the amount of benzoic acid burned is 0.7521 grams, the amount of water present within a calorimeter is 1000 grams and there is an elevation in temperature of 3.60 °C. The heat of combustion of benzoic acid given is -26.42 kJ per mole.
Now the amount of heat discharged in a reaction is:
= 0.7521 grams × -26.42 kJ / gram = -19.872 kJ or -19870 J
qreaction = - (qwater + qcal)
-19870 J = - (mwatersΔT + CcalΔT
= - [(1000 grams × 4.184 J/g degree C × 3.60 degree C) + (Ccal 3.60 °C)] (The specific heat of water is 4.184 J/gram °C)
(1000 gram × 4.184 J/g °C × 3.60 °C) + (Ccal 3.60 °C) = 19870 J
15062 J + Ccal 3.60 °C = 19870 J
Ccal 3.60 °C = 4807.6 J
Ccal = 4807.6 J / 3.60 °C = 1335.4 J/°C or 1.3 kJ/°C.