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Find the perimeter of the right triangle. If necessary, round to the nearest tenth.

A right triangle with side 13 inches, side 14 inches, and blank hypotenuse.
a.
91 in.
b.
46.1 in.
c.
19.1 in.
d.
182 in

Find the perimeter of the right triangle. If necessary, round to the nearest tenth-example-1

2 Answers

1 vote

Answer:19.1

Explanation:

Find the perimeter of the right triangle. If necessary, round to the nearest tenth-example-1
User Donavin
by
4.4k points
2 votes

Answer:

B. 46.1 in

Explanation:

First, we must find the hypotenuse of the triangle.

Since this is a right triangle, we can use Pythagorean Theorem.

a^2+b^2=c^2

where a and b are the legs and c is the hypotenuse.

13 and 14 are the legs, because they form the right angle. x is the hypotenuse because it is opposite the right angle.

13^2+14^2=x^2

Evaluate each exponent.

13^2=13*13=169

14^2=14*14=196

169+196=x^2

Add 169 and 96

365=x^2

Take the square root of both sides.

√365=√x^2

√365=x

19.1049732=x

Round to the nearest tenth.

19.1=x

The hypotenuse is 19.1 inches

Now, find the perimeter. Add up all the sides of the triangle: the legs (13 in and 14 in) and the hypotenuse (19.1 in)

13 in +14 in +19.1 in

46.1 in

The perimeter is 46.1 inches and B is correct.

User Ny
by
4.7k points