Answer:
CD = 14
Explanation:
Theorem of chords in a circle says,
If two chords are equidistant fro the center in a circle, then the chords will be equal in measure.
Therefore, AB ≅ CD
And a perpendicular drawn from the center bisects the chord in a circle.
AE ≅ EB ≅ 7 units
AB = AE + EB
AB = 2(EB)
Since CD = AB = 2(EB)
CD = 2×7 = 14 units
CD = 14 will be the answer.