Answer:
P(10 packet) = 0.000976
Therefore, there is a 0.000976 probability of packet loss if the number of packets in residence is limited to 10.
Explanation:
We are given an M/M/1 queuing system
The mean arrival rate is
λ = 500 packets/second
The mean service rate is
μ = 1000 packets/second
The number of packets in residence is
n = 10
The probability of packet loss is given by
P(n packet) = ρⁿ
When n is the number of packets and ρ is the gateway utilization
The gateway utilization is given by
ρ = λ/μ
Where λ is the mean arrival rate and μ is the mean service rate.
ρ = 500/1000
ρ =0.50
So, the probability is
P(10 packet) = (0.50)¹⁰
P(10 packet) = 0.000976
Therefore, there is a 0.000976 probability of packet loss if the number of packets in residence is limited to 10.