Question

A cylindrical specimen of some metal alloy having an elastic modulus of 106 GPa and an original cross-sectional diameter of 3.9 mm will experience only elastic deformation when a tensile load of 1660 N is applied. Calculate the maximum length of the specimen before deformation if the maximum allowable elongation is 0.41 mm.

Answer 1

L= 312.75 mm

Step-by-step explanation:

given data

elastic modulus E = 106 GPa

cross-sectional diameter d = 3.9 mm

tensile load F = 1660 N

maximum allowable elongation ΔL = 0.41 mm

to find out

maximum length of the specimen before deformation

solution

we will apply here allowable elongation equation that is express as

ΔL =
`(FL)/(AE)` ....................1

put here value and we get L

L =
`(0.41* 10^(-3)* (\pi)/(4)* (3.9* 10^(-3))^2* 106* 10^9)/(1660)`

solve it we get

L = 0.312752 m

L= 312.75 mm