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A random variable r is normally distributed with a mean of 7 and a standard deviation of 1.5. Find the value of w so that P (8.8

User Elyograg
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Answer:

The answer is explained below

Explanation:

Given that:

mean (μ) = 7 and standard deviation (σ) = 1.5.

The z score is used in statistic used to measure the number of standard deviation by which the raw score is above or below the mean value. It is given by:


z=(x-\mu)/(\sigma), where\ x\ is\ the \ raw\ score

To find the Probability that x < 8.8, we first find the z score using:


z = (x-\mu)/(\sigma)=(8.8-7)/(1.5)=1.2

From the z tables, P(x < 8.8) = P(z < 1.2) = 0.8849 = 88.49%

User Ecoplaneteer
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