Question

Identify the limiting reactant when 32. 0 g hydrogen is allowed to react with 16. 0 g oxygen

Answer 1

Oxygen is limiting reactant

Step-by-step explanation:

2 H2 + O2 ======> 2 H2 O

from this equation (and periodic table) you can see that

4 gm of H combine with 32 gm O2

H / O = 4/32 = 1/8

32 /16 = 2/1 shows O is limiter

for 32 gm H you will need 256 gm O and you only have 16 gm