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One-quarter of the Math Olympiad participants are two-thirds of the Genius Circle students. Eight Genius Circle students did not participate in the Olympiad. What is the total number of students who participated in the Math Olympiad?'

User Hetsgandhi
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2 Answers

3 votes

Answer:

64

Explanation:

This question is actually not hard just requires careful calculations.

So we know that 1/4 of MO (Math Olympiad) = 2/3 of GC (Genius Circle)

It also gives that 8 GC Members did not go to MO

So using these statements, we can find that

a. 1/3 of GC = 8 members --> and

b. 2/3 of GC = 16 which makes -->

c. 1/4 of MO = 16

Using these statements we can simply calculate 16 x 4 = 4/4 = 1

1 = Total amt. of participants in the MO => 16(4)

64

Hope this helps!

User Mitch Lindgren
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1 vote
Answer: First let’s find how many student are in Genius Circle and we assume it’s Y
Then we have the equation:
2/3Y + 8 = Y
8 = 1/3Y
8 x 3 = Y
24=Y
Now that we know what is Y we can substitute: 2/3Y = 2/3 x 24 = 16
If 16 of the Genius Circle participants equal to 1/4 of the participants of the Math Olympiad which mean:
1/4 = 16
4/4 = 16 x 4
4/4 = 64
And so the answer for the total number of the participant in the Math Olympiad is 64.

User Shahbaz Akram
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