Question

2S+3O2=2SO3. If 4moles of sulfur reacts with 9. 5 moles of oxygen, how many moles of oxygen would remain after the reaction?

Answer 1

Answer: 3.5 moles

Step-by-step explanation:

For every 2 moles of sulfur consumed, there are 3 moles of oxygen consumed.

This means that sulfur is the limiting reactant, meaning that 2(3)=6 moles of oxygen will be consumed.

Thus, 9.5-6=3.5 moles of oxygen will remain.