Question

Bucket contains 425 mL of water. The capacity of water in the bucket decreases 4.8% each hour. Which equation models the situation?

Answer 1

`V(t) = 425(0.952)^(t)`

Explanation:

The amount of water in the bucket after t hours, in mL, can be modeled by an equation in the following format:

`V(t) = V(0)(1-r)^(t)`

In which V(0) is the initial amount, and r is the constant decay rate, as a decimal.

Bucket contains 425 mL of water.

This means that
`V(0) = 425`

The capacity of water in the bucket decreases 4.8% each hour.

This means that
`r = 0.048`

So

`V(t) = V(0)(1-r)^(t)`

`V(t) = 425(1-0.048)^(t)`

`V(t) = 425(0.952)^(t)`