Answer:
1. ∆CBD: ∠B = 70°; ∠BCD = 20°; ∠ BDC = 90°
2. ∆CDA: ∠ACD = 70°; ∠A = 20°; ∠ ADC = 90°
Explanation:
1. ∆DBC
In ∆ABC
∠A + ∠B + ∠C = 180°
20° + ∠B + 90 ° = 180°
∠B + 110 ° = 180°
∠DBC = ∠B = 70°
In ∆CBD
∠BDC = 90°
∠B + ∠BCD + ∠CBD = 180°
70° + ∠BCD + 90 ° = 180°
∠BCD + 160° = 180°
BCD = 20°
2. ∆CAD
∠A + ∠ACD + ∠ADC = 180°
20° + ∠ACD + 90° = 180°
∠ACD + 110° = 180°
∠ACD = 70°