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Determine the magnitude of the force between two 11 m-long parallel wires separated by 0.033 m, both carrying 5.2 A in the same direction.

User Koraktor
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1 Answer

2 votes

Answer:


F=1.8* 10^(-3)\ N

Step-by-step explanation:

We have,

Length of wires is 11 m

Separation between wires is 0.033 m

Current in both the wires is 5.2 A

It is required to find the magnitude of force between two wires. The force between wires is given by :


F=(\mu_o I_1I_2l)/(2\pi r)\\\\F=(4\pi * 10^(-7)* 5.2* 5.2* 11)/(2\pi * 0.033)\\\\F=1.8* 10^(-3)\ N

So, the magnitude of force between wires is
1.8* 10^(-3)\ N

User Rahmel
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6.4k points