Answer: 10/21
Explanation:
From the question, we are told that two urns both contain green balls and red balls. Urn I contains 4 green balls and 8 red balls and Urn II contains 2 green balls and 5 red balls.
Urn 1 contains 4 green balls and 8 red balls. This means that the probability of drawing a red ball in urn 1 will be 8/12 = 2/3.
Urn II contains 2 green balls and 5 red balls. This means that the probability of drawing a red ball in urn 2 will be 5/7
Since we've the probability of drawing a red ball from both urns, we then multiply them together. This will be:
= 2/3 × 5/7
= 10/21