Question

Find the values of y = p(x) = √x for x = 0, 1.44, 2.25, 3.24, 4.41, 5.29.

Answer 1

The correct answers are:

`√(0)=0\\√(1.44) = \pm 1.2\\√(2.25) = \pm 1.5\\√(3.24) = \pm 1.8\\√(4.41) = \pm 2.1\\√(5.29) =\pm 2.3`

Explanation:

Given the function:

`y=p(x)=√(x)`

That means, the value that we give as input i.e. the value of x is square rooted and given as output.

Input is x and output is
`\sqrt x`.

Now, calculating the outputs for different values of x:

1. x = 0, the square root of 0 is always 0.

so, y = p (0) = 0

2. x = 1.44

`y = p(1.44)=√(1.44) \\\Rightarrow \sqrt{\frac{144} {100}}\\\Rightarrow \pm \frac{12} {10} = \pm 1.2`

Similarly other square roots can be calculated:

3. x = 2.25

`y = p(2.25)=√(2.25) \\\Rightarrow \sqrt{\frac{225} {100}}\\\Rightarrow \pm \frac{15} {10} = \pm 1.5`

4. x = 3.24

`y = p(3.24)=√(3.24) \\\Rightarrow \sqrt{\frac{324} {100}}\\\Rightarrow \pm \frac{18} {10} = \pm 1.8`

5. x = 4.41

`y = p(4.41)=√(4.41) \\\Rightarrow \sqrt{\frac{441} {100}}\\\Rightarrow \pm \frac{21} {10} = \pm 2.1`

6. x = 5.29

`y = p(5.29)=√(5.29) \\\Rightarrow \sqrt{\frac{529} {100}}\\\Rightarrow \pm \frac{23} {10} = \pm 2.3`

Hence, The correct answers are:

`√(0)=0\\√(1.44) = \pm 1.2\\√(2.25) = \pm 1.5\\√(3.24) = \pm 1.8\\√(4.41) = \pm 2.1\\√(5.29) =\pm 2.3`