Question

What are the coordinates of the terminal point for 0=5pie/6

Answer 1

`p((5 \pi)/(6) ) = (- (√(3) )/(2) , (1)/(2) )`

Explanation:

`cos((5 \pi)/(6) )=(√(3) )/(2)`

`sin((5 \pi)/(6) ) = (1)/(2)`

(5π)/6 is in quadrant II, so..

`cos((5 \pi)/(6) ) < 0`

`sin((5 \pi)/(6) ) > 0`

The points are:

`p((5 \pi)/(6) ) = (- (√(3) )/(2) , (1)/(2) )`

Answer 2

P(
`(5\pi )/(6)`) = ( -
`√(3) / 2` ,
`1/2` )

Explanation:

Cos
`(5\pi )/(6)` =
`√(3) / 2`

Sin
`(5\pi )/(6)` =
`1/2`

Since
`(5\pi )/(6)` lies in Quadrant II , So Cos
`(5\pi )/(6)` < 0, Sin
`(5\pi )/(6)` > 0

So,

The coordinates are P(
`(5\pi )/(6)`) = ( -
`√(3) / 2` ,
`1/2` )