Question

The function h(t) = 2.3 + 50t - 1.86t^2 models the height of an arrow shot from a bow on Mars, where h(t) is the height in metres and t is time in seconds. How long does the arrow stay in flight?

Answer 1

The arrow stay in flight for 26.92 seconds

Explanation:

We are given that the height of an arrow shot from a bow on Mars is modeled by equation:

`h(t) = 2.3 + 50t - 1.86t^2`

Where h(t) is the height of arrow

t is the time in seconds

Now we are supposed to find How long does the arrow stay in flight?

Substitute h(t)=0

So,
`2.3+50t-1.86t^2=0`

`1.86t^2-50t-2.3=0`

t=-.04 , 26.92

Since the time cannot be negative

So,the arrow stay in flight for 26.92 seconds