Question

SOMEONE HELP! (b+3)(c-4)

Answer 1

`bc - 4b + 3c - 12` apply de disruptive property by multiplying each term of b+3 by each term of c -4

Answer 2

`bc - 4b + 3c - 12`

solution,

`(b + 3)(c - 4) \\ = b(c - 4) + 3(c - 4) \\ = bc - 4b + 3c - 12`

hope it helps..