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5 votes
How much heat does it take to raise the temperature of 7.0 kg of water from

25-C to 46-C? The specific heat of water is 4.18 kJ/(kg.-C).
Use Q = mcTr-T)
A. 148 kJ
B. 176 kJ
C. 610 kJ
D. 320 kJ​

User Rodger
by
5.8k points

2 Answers

6 votes

Answer:

non of the above

Step-by-step explanation:

Quantity of heat = mass× specific heat× change in temperature

m= 7kg c= 4.18 temp= 46-25=21°

.......H= 7×4.18×21= 614.46kJ

User Jirik
by
5.3k points
4 votes

Answer:610 KJ

Explanation:A P E X answers

User Alex Nelson
by
5.1k points