Question

What is the molarity of a saline solution that contains 0.900g NaCl (58.44 g/mol) dissolved in 100.0 mL of solution?

Answer 1

Hey there!:

Molar mass NaCl = 58.44 g/mol

Number of moles = mass of solute / molar mas

Number of moles = 0.900 / 58.44

Number of moles = 0.0154 moles of NaCl

Volume in liters of solution :

100.0 mL / 1000 => 0.1 L

Therefore:

Molarity = number of moles / volume in liters

Molarity = 0.0154 / 0.1

Molarity = 0.154 M

Hope this helps!