Question

Please help. What is the equation of the line in slope-intercept form?​

Answer 1

y = mx + b

m = slope

b = intercept

From the graphic:

(x₁, y₁) = (0, 4)

(x₂, y₂) = (4, 0)

`(y-y_(1) )/(y_(2) -y_(1) ) =(x-x_(1) )/(x_(2) -x_(1) ) \\\\(y-4 )/(0 -4) =(x-0 )/(4 -0 ) \\\\(y-4)/(-4) =(x)/(4) \\\\(y-4)4=-4x\\\\y-4=-x\\y=-x+4\\`

Answer 2

Ray, you need the slope-intercept formula y=mx+b

Explanation:

Next you'll need 2 points, any points are fine. Just find two easy ones along the line. I'll just pick Point 1 as P1 = ( 0,4) and point 2 as P2 = (4,0) because they are easy to work with.

next use

point P1 (0,4) in the form (x1,y1)

point P2(4,0) in the form (x2,y2)

slope = m

m = (y2-y1) / (x2-x1)

m = (0-4) / (4-0)

m = -4 / 4

m = -1

now use the point slope with one of the points, to find the slope-intercept form.

y - y1 = m(x -x1)

y - 4 = -1(x-0)

y -4 = -x

y = -x + 4

note:

y = mx +b

y = (-1)x + b is the form. see?