Question

What is the solution to the equation Two-thirds x + 1 = one-sixth x minus 7? x = negative 16 x = negative 4 x = 4 x = 16

Answer 1

x = -16

Explanation:

I was able to come to this conclusion by first giving
`(1)/(6)` and
`(2)/(3)` a common denominator.

`(4)/(6) x +1 = (1)/(6)x -7`

From here all I had to do was simply simplify on both sides so I subtracted
`(1)/(6)` from both sides of the equation and got

`(3)/(6)x + 1 = -7`

From the there I then subtracted the 1 from both sides of the equation so that the variable and the real number would be on different sides of the equal sign.

`(3)/(6)x = -8`

Then I had to isolate the
`x` so I divided both sides by
`(3)/(6)` and got -16.

Answer 2

x = -16

Explanation:

Step 1: Write out equation

2/3x + 1 = 1/6x - 7

Step 2: Subtract 1/6x on both sides

1/2x + 1 = -7

Step 3: Subtract 1 on both sides

1/2x = -8

Step 4: Multiply 2 on both sides

x = -16