Question

How much heat will be absorbed by a 63.1 g piece of aluminum (specific heat = 0.930 J/g･°C) as it changes temperature from 23.0°C to 67.0°C?

Answer 1

`Q=2582J=2.58kJ`

Step-by-step explanation:

Hello,

In this case, for us to compute the absorbed heat, we apply the following equation:

`Q=m_(Al)Cp_(Al)(T_2-T_1)`

Whereas we use the mass, specific heat and temperature change for the piece of aluminium, thus, we obtain:

`Q=63.1g*0.930(J)/(g*\°C)*(67.0-23.0)\°C\\ \\Q=2582J=2.58kJ`

It is positive as the heat is entering, therefore the temperature raises.

Best regards.